I am wiring up a new thermostat for an old boiler, and the thermostat I am using needs a common wire (Proliphix NT130h — I wanted an NT1X0e
series, which use PoE and don't need C
, but they are no longer available).
The system uses a Honeywell "aquastat" controller that has an integrated transformer hooked up to Rh
and W
, so there's no way to add a common C
to that transformer (short of what this guy did with taking apart the control unit and soldering a wire to the back of the board).
Here's what it looks like (though this is a much newer model, it looks pretty much the same):
Luckily, I have an additional 24VAC transformer right next to the boiler that I can use (it was meant to be used to power the thermostat for an air conditioning unit, but that unit was never installed, only the thermostat power and wires.
I know that I can theoretically use that transformer to power the thermostat by hooking it up to Rc
and C
. However, the installation manual notes that C
must be in phase with Rh
, which is not the case in my installation which has C
in phase with Rc
.
Since I don't think it will work to use only a single wire from the transformer (even though the manual says "in phase", I assume that it actually means "complete circuit"), I am trying to figure out another way to do this.
What I would like to do is hook up the heat through a relay.
That way, I can send power to the thermostat without needing separate Rh
and Rc
(in fact, since there is no AC, without needing Rc
at all).
As I envision it, when the thermostat calls for heat, it will connect Rh
to W
which will connect the trigger side of the relay, which will close the circuit on the heater wires that used to go to Rh
and W
.
I have two concerns:
- Is there any special relay I need, or will anything I find designed for low voltage work?
- Do I need to worry that either side of the relay won't have enough of a load on it, possibly causing the equivalent of a short circuit on either of the transformers?
Best Answer
I talked to a local HVAC repairman, and he said it should work, so I did it, and it works.
Here's what the circuit looks like: