Have 30 75-watt lights in a 15-amp circuit breaker and 230 volts

circuit breaker

The voltage here in the Philippines is 230 volts. I searched for the calculation of the capacity of a circuit breaker. So I found out that 15-amp breaker at 230 volts can handle 15x230x.80 percent = 2760 watts. Now, 2760 watts/75 watts = 36.8 lights. So, if I understand correctly, I can install 30 lights in a 15-amp breaker. However, I don't want to miss something, is this calculation correct? Also, will it be fine if I will turn on all 30 lights at the same time?

EDIT
We will use #14 thick wire. Is this also correct?

Thanks!

Best Answer

Strictly speaking, you are correct. The circuit can handle 15 A * 230 V = 3450 W before tripping*. As a safety margin, you want to stay below 80% of that, or 2760 W. Your 30 bulbs, at 75 W per bulb, draw 2250 W total, which is within the safe operating load of the circuit. So, from a physical standpoint, you're good. #14 wire is appropriate for a 15 A circuit.

However, as mentioned, you want to be aware of any local codes which limit the number of fixtures or receptacles on the circuit. As @isherwood mentions, too, you may want to consider a lower-power bulb (like LED or CFL) if it works in your situation, or an alternative lighting solution - e.g., do you really need 30 bulbs? Could you get the same result using half as many bulbs that output more light? 2200 W is a lot of power usage for lighting, so any way you can reduce that will be beneficial to your wallet :)


*In a perfect world. In the real world, breakers don't trip immediately when reaching their current limit, etc, etc.