Switch – Why does this switch throw the breaker when turned on

circuit breakerreceptacleswitch

I volunteered to help a friend with an electrical problem she was having – two of the receptacles in her bedroom did not work.
All the receptacles that I looked at had two black wires and two white wires, which I interpret as they are all in the middle of a run. The wires in all the receptacles used the "push-in" connections rather than screw-down connections, and some had come loose. I replaced one of the receptacles as the push-in connectors didn't seem to grab any more. At this point, the receptacles still didn't work.
Next I went to a working receptacle in the bedroom and found the same problem, with evidence of arcing on one of the black wires. I replaced this receptacle and, Ta-Dah!, all receptacles in the bedroom worked.

Now comes the problem. There is also a switch on the wall that always appeared to do nothing. I was assuming that the switch controlled one/both of the non-working receptacles, but after my fix all the receptacles worked while the switch was in the off position. Plus, when the door is opened, the switch is behind the door; if it was intended to turn on a room light (there is no ceiling fixture), then it should probably be on the other side of the door.
Finally, when I turn the switch on, the circuit breaker trips. This is the same circuit breaker that controls the outlets in the room. The light switch is single-pole, and appears to be the end of a switch loop – the black wire goes to one side of the switch, and the white wire goes to the other side of the switch. The only other wire in that box is the ground, which is attached to the box itself.

Maybe there used to be a light fixture, and it was wire-nutted together and plastered over?
How can I trace the wires through the walls? I suppose I could simply disconnect and wire-nut (separately) the offending wires in the light switch, but I'd like to get it all set up correctly.

Best Answer

If your hypothesis is correct, which it most likely is, that the switch controls one of the outlets, then the extra pair of wires in that outlet have to do with the switch. Either they provide a separate loop to control just one half of the outlet (some switched outlets are like that: a switch just controls one of the receptacles out of the pair). Or else the extra wires are meant to be in series with the outlet, going out to the switch.

It sounds as if you miswired it so that the switch hookup is in parallel with a receptacle's hot and neutral (thinking that it's a daisy chain connection to the next outlet).

When you do that, guess what happens. Everything works when the switch is open, and when you close it, it short circuits.

A half-switched outlet, if that's what your friend has, normally requires three connections (not including ground). Two wires will come from the breaker, and two from the switch giving you four. This means two of them get connected together. How this happens is that the switch receives hot, and so it screwed to the same terminal as hot, or otherwise spliced to hot. The return wire from the switch feeds the secondary hot that controls the switched part of the receptacle.

The best way to proceed here is to turn the power off at the breaker and verify continuities: in particular, which pair of wires corresponds to the switch. With the power on, you should also check that you haven't wired any outlet with the opposite polarity: neutral being hot and vice versa.