Wiring – How dangerous is induction in the wires

switchwiring

I had to replace a cable going to a light switch. The cable was about 7m long and contained three (1.5mm^2) copper wires, with a distance of about 2mm between any two of them.


Source

One wire was the hot wire that constantly provided 230V, 50Hz alternating current to the switch, and one was going back to the light. The third one wasn't connected to anything.

I was very surprised to see that when the light was turned off (so only one of the three wires was powered), I could measure about 140V AC on the third wire compared to a grounded water pipe, using my super cheap multimeter. I didn't dare to touch it as long as any of it was powered.

I wondered, was this measurement of 140V realistic – or was my multimeter just faulty? And how much current could this cable have provided?

I have no idea how to estimate whether this was realistic so I'd be very happy to learn whether there are any formulas to approximate these values.

Best Answer

The key point in your question is that it happens when the light is off. In this case, the alternating current in the live wire produces an alternativing magnetic filed around the wire which induces current in the floating wire. This induced current is also 50hz that's why you can see it when your multimeter is in the AC mode.

The reason this voltage goes away when you turn on the light is that the second wire becomes live. Since the direction of current is opposite in the second wire its magnetic field is the opposite of that of the first live wire and it cancels the other magnetic field. I.e., one magnetic field is clockwise and the other counter clockwise at any moment in time. So no induced current.

When the light is off there is no current in the live wire so when you put any load on the float wire the induced voltage probably goes to 0.