I was bored, so decided to make this monstrosity of a redstone circuit:
Edit: Now that Redstone Repeaters have been added to the game, even by following this design, sections 3 and 7 could be greatly diminished (as those sections are basically just repeaters).
This circuit will accomplish what your question is asking. I will explain each section of the circuit:
Red Square (#1)
This is the pressure plate the player will stand on. The end result is that your door will open if the player is standing on it, and will close when the player steps off. Also, if a certain amount of time passes by, the door will close even if the player is still stepping on the plate.
Orange Square (#2)
These are known as edge triggers. If they receive an input, their output will flash for one tick (redstone timing is measured in ticks) and stay off after that, even if the input is still receiving power.
Brown Square (#3)
This may look like a mess of NOT gates, and that's because it is a mess of NOT gates. Specifically, it is a mess of an odd number of NOT gates. This is known as a clock generator. A clock causes its output to cycle on and off continuously. The number of NOT gates in it determines the duration of the cycle (more repeaters equals a longer time spent on and off).
The clock is off, because 3a is sending it power. If the player were to step on the pressure plate, 3a would turn off, causing the clock to begin cycling.
This is one of the ways you can adjust the inactivity timeout - if you need it to last longer, add more NOT gates, and vice versa.
Dark Green Square (4)
Note that this device is multiple levels, most of which are not shown in this image. I only included it as a visual aid to show its input and outputs. If you build this circuit and wonder why it doesn't function, this is why.
This is a binary counter. Every time the torch at 4b, receives power, it counts in binary. This is the reason you need the clock - so the input will flash on and off, causing the binary counter to...count. The first flash causes the rightmost torch to turn on (00001). The next flash results in 00010, then 00011, 00100, etc. 4a is the binary counter reset, causing the torches to read 00000. This ensures that when the player steps on the plate, the counter will start fresh.
Because you will have to build a binary counter that actually works, see the schematic of one from this thread on the Minecraft Forums.
Adding or removing more bits to the binary counter is the other way you can adjust the duration of the timeout.
Teal Square (5)
Basically, when the binary counter reads 11111 (all of the torches are on), 5a will turn on, causing the RS-NOR latch at 6 to turn off regardless of whether or not the player is still on the pressure plate (RS-NOR latch explained later).
Purple Square (6)
This is an RS-NOR latch. It is effectively a 1-bit memory cell, storing either a 0 or a 1. When the block in the bottom-left corner of it receives power, the switch flips into the 1 position, causing the door to open. When the block in the top-right receives power, the latch resets, causing the door to close.
Black Square (7)
This is just a bunch of repeaters (two NOT gates). The only reason for this is so that the signal going around the right side of the circuit reaches the RS-NOR latch before this signal. If there were no repeaters here, the RS-NOR latch would switch into its on state, and then switch off right after due to being reset.
Rainbow Square! (8)
Oh look, it's finally the door!
In summary, this is what happens:
- Player steps on pressure plate
- Binary clock resets
- Clock begins cycling, causing the binary clock to count up
- RS-NOR reset wire from the pressure plate turns off
- Signal travelling through the wire to the left of the plate propagates through the edge trigger, flipping the RS-NOR into its on position
- Door opens!
Then, if the player were to step off of the plate, the wire wrapping around the right side would turn on again, causing the RS-NOR to turn off and, consequently, closing the door. Additionally, if the player continues to stand on the plate and the binary counter reaches 11111, the torch at 5a turns on, also causing the door to close.
I'm sure this circuit could be made much smaller and more efficient, but this is a proof of concept.
Since there is no answer I will show how to make a random unit:
If you are not ready to have your mind blown go to conclusion at the end.
Take a 3-clock unit and set an output somewhere, now since this is only 3-clock it's gonna burn at RANDOM place so the output will be random. Like this:
Now you probably don't want it to change so much but only when it stopped, well.. idk if anyone used it(probably used), anyway I've made it my self, I call it "signal cuter" the point is to split the signal into 2 signals: first contain odd number of "not gates" and the second even, and then merge them into "or gate", the result is: when a signal is sent, it's gonna stay as the output until the second path will cut the signal and that way no matter for how long you set the input to "on", the output gonna be "on" only for length(second path) - length(first path) "ticks".
in this example, all signals that are more then 3 ticks length are shorted to 3 ticks long. On same property you can make a "signal protector" also made by me :), it's not passing signals less than X long all the difference is that both paths first and second need to be odd length and the X is equal to length(second path) - length(first path), but the signal become shorter then the original signal length. Example:
FINALLY the conclusion: so now you can take the a 3-clock and to chain it with the "signal protector" with X=2 and THIS WILL BE STABLE!! It won't throw junk until the 3-clock burned and the result is stable, the next random will be generated after the next 3-clock burn, if you want to make it faster just make many units of that.
THE RESULT:
It's still throw junk in "Redstone Simulator" but in "Minecraft" this works great!
Please if you're passing on this technique, leave the names "Signal Cutter" and "Signal Protector".
Best Answer
When I read the question, I quickly thought that a memory cell could be involved somewhere in the solution. But actually, a memory cell (with one input inverted) is already all you need!
Imagine that the comparator comes from your minecart and the button is just your button. The redstone lamp is the output for emptying the minecart.
When the minecart arrives with items, it turns on the comparator, which turns off the redstone lamp on the left and the redstone dust. Nothing else happens, because the memory cell still holds its state, that's the point of a memory cell.
When you now press the button, the bottom redstone torch and the left repeater turn off, which allows the top right redstone torch to turn on (since it's also not deactivated by the redstone line anymore), which turns on the output and the repeater on the right.
When the button input ends, the bottom redstone torch still does not turn on, because the right repeater is still on. Again, what a memory cell is supposed to do.
Only when the comparator turns off and the left redstone torch and the dust turn on again, then the top right redstone torch turns off again, deactivating the right repeater, activating the bottom redstone torch and the left repeater.
Special cases: