[RPG] Can you stand from prone if your speed is 5 and you have no movement remaining

dnd-5emovementprone

This is inspired by the following question:

The answers there state that, assuming we are on a grid, if you have 35 speed and you are prone it takes 15 movement to stand up which leaves you with 20 movement leftover. Similarly then, if your speed was 15 it would take 5 movement to stand and you would have 10 movement left over. But what about when your speed is 5; does it require 0 movement and so you have 5 movement leftover? The section on being prone states:

[…] You can't stand up if you don't have enough movement left or if your speed is 0.

Here our speed is not 0 and we do have enough movement left (0 movement); it seems to me that this is technically valid then. I'm just wondering if there's a rule I've missed somewhere or if it is in fact possible for a creature to stand from prone while having 0 movement available, given that their speed is 5?

In other words, following the logic of those answers, it should take 0 movement to stand up if your speed is 5. Is this the case?

Best Answer

No

I have my own issues with the answers on the linked question, and have posted an opposing answer there, but I will rehash the point here.

The rules for movement on a grid state (PHB, p.192)

Rather than moving foot by foot, move square by square on the grid. This means you use your speed in 5-foot segments.

This does not say all movement distance (or required expenditure) is calculated in 5 feet increments, it only describes how the player expends their movement. Therefore, the cost of standing up while prone is still 2.5 feet of movement for this character. (Probably rounded down to 2).

If the player has 0 movement remaining, they do not have enough movement (2 feet) and therefore cannot stand up while prone.

TL;DR the premise of this question was based on (what I believe to be) faulty assumptions made within the answers of the parent question.