[RPG] Do damage modifiers add individually to each die of a rogue’s sneak attack damage

damagednd-5erogue

In d&d 5e
When it comes to a rogue's sneak attack, let's use a 6th level with a short bow with 18 dex as the example character(which is a 3d6 sneak attack), do you add the +4 for the bow to each individual d6 roll? Making it +16. That's kinda high, so that's why I'm asking.
Example encounter: there's an ogre and the party's paladin is with 5 feet of it. The rogue draws and fires on it, hitting it, 1d6+4 for the shortbow, then 3d6 for the sneak attack with +4 for each d6?(the total plus being +16)

I hope that kinda makes sense. In short, do you add your dex modifier to each of your sneak attack's d6s?

Best Answer

No, your attribute's modifier gets added to your total damage, not to each individual die.

PHB, p. 196:

You roll the damage die or dice, add any modifiers, and apply the damage to your target.... When attacking with a weapon, you add your ability modifier -- the same modifier used for the attack roll -- to the damage.

PHB, p. 96:

Once per turn, you can deal an extra 1d6 damage to one creature you hit with an attack...

Likewise, if a character had a Strength bonus of +4 to damage and was attacking with a greatsword (2d6 dmg), they would add a total of +4 to damage, not +8.