[RPG] How cumulative chance is calculated in Augury or similar spells

dnd-5espells

Part of the augury spell description says:

If you cast the spell two or more times before completing your next long rest, there is a cumulative 25 percent chance for each casting after the first that you get a random reading. The DM makes this roll in secret.

How should I roll this cumulative chance?

  1. Using a single d4. A second casting of augury means that rolling 1 results in a random reading. A third casting means that rolling 1 or 2 results in a random reading, and so on.

  2. Using more d4. A second casting of augury means that you roll 1d4, and if a 1 is rolled, it results in a random reading. A third casting means that you roll 2d4, and a 1 rolled on either die results in a random reading, and so on.

Best Answer

"Cumulative" in this context means Additive

Cumulative is a word formed from shortening "Accumulative", which means to add together. So when the text reads "a cumulative 25% chance of failure per casting", it's intended to mean "accumulate 25 percentage points worth of chance per casting".

Because of this, it is correct to treat the math as being (X / 4) chance of failure (random result), where X is the number of times prior to the current casting of Augury that you've cast Augury. This means that on the first casting, there's a 0% chance of failure, then a 25% chance, then 50%, then 75%, and on the fifth casting onwards, the result is always random.

Either roll a single d4, like you suggested, using rolls of (1,2,3,4) as the minimum required for success for each successive roll, or use d% when making this roll, using (1, 26, 51, 76) as the minimum required rolls for success.

If the rules intended you to roll multiple dice for a multiplicative calculation, like your second option suggests, the rules would expressly instruct you to do that.

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