[RPG] What happens when you deal damage with a raise but the victim is already shaken

savage-worldsshaken

Let's say a wild card foe gets shaken (either through damage or other means). Per the rules, if she gets "shaken again" through successful damage, she gets a wound instead (and remains shaken).

What if a PC successfully hits her and beats her toughness with a raise (instead of simply beating it)? Does the foe get one wound or two wounds (one for being shaken again and the other for the raise)?

Best Answer

The process for determining whether a target hit for damage is shaken and/or wounded can be summed up as follows:

If the target is not Shaken

  • A success on the damage roll = Shaken
  • 1 Raise = 1 Wound and Shaken
  • 2 Raises = 2 Wounds and Shaken
  • 3 Raises = 3 Wounds and Shaken
  • And so on...

If the target is Shaken

  • Success = 1 Wound and remains Shaken
  • Raise = 1 Wound and remains Shaken
  • 2 Raises = 2 Wounds and remains Shaken
  • 3 Raises = 3 Wounds and remains Shaken
  • And so on...

The important part (and where a lot of players get it wrong) is how a success and the first raise affect a target that is already shaken. The reason for the game being designed like this has been explained as 'because it makes it easier for a Shaken Wildcard to be wounded but not seriously wounded'.

See here for an official take on this subject, which gets asked A LOT on the official forums.

An additional post with a more detailed breakdown can be found here.

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