[SalesForce] How to insert a string into another string

I am having a string String S1="https://www.microsoft.com/s/5f5wpyvu1cbdek2ld3as"

I am having another string String S2="0000000/demowidget".

I want to insert my new string S2 into my old string S1 just before "/s"

any help?

Best Answer

Lets say you have the following strings.

String1 = 'myString/myPattern/someString'
String2 = 'newString'

You can append your new string just before the required pattern like this.

String newString = 
    String1.substring(0, String1.indexOf('/myPattern')) +
    String2 + 
    String1.substring(String1.indexOf('/myPattern'), String1.length());

But make sure your pattern is not repeated in the String1, because you might end up replacing just the first occurrence.

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[SalesForce] Problem using string replace method

Strings are immutable which means that they cannot be modified. When you call an instance operation on a String it creates a new String instance to return.

You need to assign the result to another variable (or to the variable itself).

For example:

Descrip = Descrip.replace(string.valueOf(oEvtOwnrs.get(ev.WhatID))), string.valueOf(nEvtOwnrs.get(ev.WhatID)));

[SalesForce] How to snip and pass a string value between brackets to a Map

The code below will get the text from within the brackets. The code makes use of some String methods

String eDescription = 'This is (the test) text';
Integer openingIndex = eDescription.indexOf('(');
Integer closingIndex = eDescription.indexOf(')');
String textInBrackets = eDescription.subString(openingIndex + 1, closingIndex);

Using @Sovereigntys suggestion of using substringBetween then the code becomes:

String eDescription = 'This is (the test) text';
String textInBrackets = eDescription. substringBetween('(', ')');

FYI: Both ways will find the first instance of '(' and ')'.

Input: 'This is (the test) text', Output: 'the test'
Input: 'This is (the test) (text)', Output: 'the test'

Best Answer

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[SalesForce] How to snip and pass a string value between brackets to a Map

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