[SalesForce] Replace String with Wildcard

Is it possible to replaceall on a string using wildcards?
For example

string adder;
adder = '[Test | 123 ! xyz]';
string replaced;
replaced = adder.replaceall('|%!','');

System.AssertEquals(replaced,'Test xyz');

Here I am using % as wildcard but it is not working.

Best Answer

The documentation for the replaceAll() method says that it accepts a Regular Expression as the first argument. If you wanted to get rid of everything between | and ! inclusive you can use adder.replaceAll('(\\|.*!)','');.

Related Solutions

[SalesForce] How to remove ( from the string

Something like :

String s = '(09890)';
Integer i = Integer.valueOf(s.replaceAll('[\\(\\)]',''));

[SalesForce] Keyword search in string

Some people, when confronted with a problem, think "I know, I'll use regular expressions." Now they have two problems.

They really are the right tool for the job here though.

static Boolean keywordSearch(String input, String keywordPhrase)
{
    return Pattern.compile('(?i)\\b' + keywordPhrase + '\\b').matcher(input).find();
}

String corpus = 'The quick brown fox jumps over the lazy dog';
system.assert(keywordSearch(corpus, 'lazy dog'));
system.assert(keywordSearch(corpus, 'QUICK'));
system.assert(!keywordSearch(corpus, 'jump'));

The \b character indicates a word boundary. Wrap your phrase in that and see if it's in the input. The (?i) argument makes the whole thing case-insensitive.

Best Answer

Related Solutions

[SalesForce] How to remove ( from the string

[SalesForce] Keyword search in string

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