[SalesForce] Replacing Regex Match with Blank space

This should be a simple question, but I cannot find the answer. I need is to replace my Regex Match with blank space. What is the Syntax for this? Here is my Expression:

Matcher alphaSourceMatch = Pattern.compile('(?mi)<\\/?\\w*\\b[^>]*>').matcher(alphaSource);

I would simply like to replace the pattern with ' '.

Best Answer

You just need to append the .replaceAll(' ') method to your Matcher instance to replace every match with a space.

Matcher alphaSourceMatch = Pattern.compile('(?mi)<\\/?\\w*\\b[^>]*>').matcher(alphaSource);
String replacedText = alphaSourceMatch.replaceAll(' ');

Docs: Matcher.replaceAll(string)

Related Solutions

[SalesForce] Unable to use multiline with pattern

You can use the mode modifier (?m) at the beginning of your regex pattern to specify the multiline option.

String testString = 'Line 1: Does not match\nCustomer Name: Bob Dole';
String regex = '(?m)^\\s*Customer Name\\s*:\\s+(.*)$';

Matcher m = Pattern.compile(regex).matcher(testString);

// iterate through testString finding subsequent matches
while (m.find()) {
    system.debug(m.start() + ': ' + m.group());
}

Debug output:

DEBUG|23: Customer Name: Bob Dole

There are a few other helpful option modifiers that can be used with the regex pattern at the beginning of the string: regular-expressions.info - Using Regular Expressions in Java

[SalesForce] Regex Pattern/Matcher to match a exact word

Found the issue. It was not with the Regex pattern but with the Apex code.

 String strRegEx = '\\bhot\\b';
 String str = ' how hot is it';

 Pattern MyPattern = Pattern.compile(strRegEx);
 Matcher MyMatcher = MyPattern.matcher(str);
 Boolean result = MyMatcher.find();

Best Answer

Related Solutions

[SalesForce] Unable to use multiline with pattern

[SalesForce] Regex Pattern/Matcher to match a exact word

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