[SalesForce] How to remove few characters from a String

I have a string value where I am getting the a comma with } I want to remove the last , I have tried below but it is not working.

String str = '{johny:[1,2,3,4,5],erich:[5,6,7,8,9],}';
system.debug('strValue: ' + str.Substring(str.length()-2));

or tried this:

system.debug('strValue: ' + str.substring(1,str.length()-1););

result should be like this (without comma at the end):

String str = '{johny:[1,2,3,4,5],erich:[5,6,7,8,9]}';

Best Answer

String str = '{johny:[1,2,3,4,5],erich:[5,6,7,8,9],}';
system.debug('strValue: ' + str.left(str.length()-2)+str.right(1));

yields

strValue: {johny:[1,2,3,4,5],erich:[5,6,7,8,9]}

Related Solutions

[SalesForce] How to remove ( from the string

Something like :

String s = '(09890)';
Integer i = Integer.valueOf(s.replaceAll('[\\(\\)]',''));

Split the string from right side to get the required output after second occurrence of special character

This is arguably much easier with a Regular Expression:

Pattern p = Pattern.compile('(.+?)(-\\w+){2}$');
String input = 'test-string-split-exam-demo';
Matcher m = p.matcher(input);
m.find();
System.debug(m.group(1));

Where the first part (.+?) is what we want to match, and the last part (-\\w+){2}$ is what we want to ignore. Finally, group(1) gives us the first capture group, the part we wanted.

Best Answer

Related Solutions

[SalesForce] How to remove ( from the string

Split the string from right side to get the required output after second occurrence of special character

Related Topic